MathematicsQuestion 42023Mid SemesterMidsem 1hard5 marksa. Expand tan−1yx\tan^{-1}\dfrac{y}{x}tan−1xy in the neighborhood of (1,1)(1,1)(1,1) by Taylor's theorem. Hence compute f(1.1,0.9)f(1.1, 0.9)f(1.1,0.9). (2 marks)b. If u=tan−1x3+y3x+yu = \tan^{-1}\dfrac{x^3+y^3}{x+y}u=tan−1x+yx3+y3, then show that x∂u∂x+y∂u∂y=sin2ux\dfrac{\partial u}{\partial x} + y\dfrac{\partial u}{\partial y} = \sin 2ux∂x∂u+y∂y∂u=sin2u andx2∂2u∂x2+2xy∂2u∂x ∂y+y2∂2u∂y2=sin4u−sin2u.x^2\frac{\partial^2 u}{\partial x^2} + 2xy\frac{\partial^2 u}{\partial x\,\partial y} + y^2\frac{\partial^2 u}{\partial y^2} = \sin 4u - \sin 2u.x2∂x2∂2u+2xy∂x∂y∂2u+y2∂y2∂2u=sin4u−sin2u. (3 marks)Show solutionTry it yourself firstQuestion 7 of 13 in MathematicsTip: use ← → keysPrevious questionQ3 · 2023 · Midsem 1Next questionQ5 · 2023 · Midsem 1